1001001012113 has 2 divisors, whose sum is σ = 1001001012114. Its totient is φ = 1001001012112.

The previous prime is 1001001012107. The next prime is 1001001012157. The reversal of 1001001012113 is 3112101001001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 976335681409 + 24665330704 = 988097^2 + 157052^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001001012113 - 2⁶ = 1001001012049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001001012094 and 1001001012103.

It is not a weakly prime, because it can be changed into another prime (1001001012103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500506056 + 500500506057.

It is an arithmetic number, because the mean of its divisors is an integer number (500500506057).

Almost surely, 2^{1001001012113} is an apocalyptic number.

It is an amenable number.

1001001012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001001012113 is an equidigital number, since it uses as much as digits as its factorization.

1001001012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1001001012113 its reverse (3112101001001), we get a palindrome (4113102013114).

The spelling of 1001001012113 in words is "one trillion, one billion, one million, twelve thousand, one hundred thirteen".