100100110011113 has 2 divisors, whose sum is σ = 100100110011114. Its totient is φ = 100100110011112.

The previous prime is 100100110011107. The next prime is 100100110011119. The reversal of 100100110011113 is 311110011001001.

It is a balanced prime because it is at equal distance from previous prime (100100110011107) and next prime (100100110011119).

It can be written as a sum of positive squares in only one way, i.e., 77850322898089 + 22249787113024 = 8823283^2 + 4716968^2 .

It is a cyclic number.

It is not a de Polignac number, because 100100110011113 - 2¹² = 100100110007017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100100110011094 and 100100110011103.

It is not a weakly prime, because it can be changed into another prime (100100110011119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050055005556 + 50050055005557.

It is an arithmetic number, because the mean of its divisors is an integer number (50050055005557).

Almost surely, 2^{100100110011113} is an apocalyptic number.

It is an amenable number.

100100110011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100100110011113 is an equidigital number, since it uses as much as digits as its factorization.

100100110011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 100100110011113 its reverse (311110011001001), we get a palindrome (411210121012114).

The spelling of 100100110011113 in words is "one hundred trillion, one hundred billion, one hundred ten million, eleven thousand, one hundred thirteen".