Base | Representation |
---|---|
bin | 11101001000100000101… |
… | …00100101000100010101 |
3 | 10112200202111101011120211 |
4 | 32210100110211010111 |
5 | 112400022302211013 |
6 | 2043504213525421 |
7 | 132214512620011 |
oct | 16442024450425 |
9 | 3480674334524 |
10 | 1001001210133 |
11 | 3565820a5991 |
12 | 142001343871 |
13 | 7351783a782 |
14 | 3663d3cb541 |
15 | 1b0895d623d |
hex | e910525115 |
1001001210133 has 2 divisors, whose sum is σ = 1001001210134. Its totient is φ = 1001001210132.
The previous prime is 1001001210071. The next prime is 1001001210203. The reversal of 1001001210133 is 3310121001001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 549730307844 + 451270902289 = 741438^2 + 671767^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1001001210133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001001219133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500605066 + 500500605067.
It is an arithmetic number, because the mean of its divisors is an integer number (500500605067).
Almost surely, 21001001210133 is an apocalyptic number.
It is an amenable number.
1001001210133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001001210133 is an equidigital number, since it uses as much as digits as its factorization.
1001001210133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1001001210133 its reverse (3310121001001), we get a palindrome (4311122211134).
The spelling of 1001001210133 in words is "one trillion, one billion, one million, two hundred ten thousand, one hundred thirty-three".
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