Base | Representation |
---|---|
bin | 10110110000101001100110… |
… | …000111011000010100110011 |
3 | 111010102111011111211101222022 |
4 | 112300221212013120110303 |
5 | 101110020223034330001 |
6 | 552521223502502055 |
7 | 30041000535525356 |
oct | 2660514607302463 |
9 | 433374144741868 |
10 | 100100221011251 |
11 | 299932a11762aa |
12 | b28811559492b |
13 | 43b1544688476 |
14 | 1aa0c3b36429d |
15 | b88c8311411b |
hex | 5b0a661d8533 |
100100221011251 has 2 divisors, whose sum is σ = 100100221011252. Its totient is φ = 100100221011250.
The previous prime is 100100221011113. The next prime is 100100221011253. The reversal of 100100221011251 is 152110122001001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100100221011251 - 210 = 100100221010227 is a prime.
Together with 100100221011253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (100100221011253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050110505625 + 50050110505626.
It is an arithmetic number, because the mean of its divisors is an integer number (50050110505626).
Almost surely, 2100100221011251 is an apocalyptic number.
100100221011251 is a deficient number, since it is larger than the sum of its proper divisors (1).
100100221011251 is an equidigital number, since it uses as much as digits as its factorization.
100100221011251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 100100221011251 its reverse (152110122001001), we get a palindrome (252210343012252).
The spelling of 100100221011251 in words is "one hundred trillion, one hundred billion, two hundred twenty-one million, eleven thousand, two hundred fifty-one".
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