Base | Representation |
---|---|
bin | 10010101001010010… |
… | …10011111000110111 |
3 | 221211121200020021102 |
4 | 21110221103320313 |
5 | 131000033100403 |
6 | 4333142040315 |
7 | 503026010354 |
oct | 112451237067 |
9 | 27747606242 |
10 | 10010050103 |
11 | 4277459889 |
12 | 1b3441909b |
13 | c36ac8a91 |
14 | 6ad61b62b |
15 | 3d8be5b88 |
hex | 254a53e37 |
10010050103 has 2 divisors, whose sum is σ = 10010050104. Its totient is φ = 10010050102.
The previous prime is 10010050081. The next prime is 10010050129. The reversal of 10010050103 is 30105001001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10010050103 is a prime.
It is a super-2 number, since 2×100100501032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10010050403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005025051 + 5005025052.
It is an arithmetic number, because the mean of its divisors is an integer number (5005025052).
Almost surely, 210010050103 is an apocalyptic number.
10010050103 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010050103 is an equidigital number, since it uses as much as digits as its factorization.
10010050103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 11.
Adding to 10010050103 its reverse (30105001001), we get a palindrome (40115051104).
The spelling of 10010050103 in words is "ten billion, ten million, fifty thousand, one hundred three".
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