Base | Representation |
---|---|
bin | 1001000110101010100100… |
… | …0100111100010000000011 |
3 | 1022102221211210211001101112 |
4 | 2101222221010330100003 |
5 | 2303001201233211142 |
6 | 33142325314553535 |
7 | 2052130603612103 |
oct | 221525104742003 |
9 | 38387753731345 |
10 | 10010110444547 |
11 | 320a29a423714 |
12 | 11580398988ab |
13 | 577c459a54a5 |
14 | 2686c5c01203 |
15 | 1255bc86a382 |
hex | 91aa913c403 |
10010110444547 has 2 divisors, whose sum is σ = 10010110444548. Its totient is φ = 10010110444546.
The previous prime is 10010110444531. The next prime is 10010110444549. The reversal of 10010110444547 is 74544401101001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10010110444547 - 24 = 10010110444531 is a prime.
It is a super-2 number, since 2×100101104445472 (a number of 27 digits) contains 22 as substring.
Together with 10010110444549, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10010110444549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005055222273 + 5005055222274.
It is an arithmetic number, because the mean of its divisors is an integer number (5005055222274).
Almost surely, 210010110444547 is an apocalyptic number.
10010110444547 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010110444547 is an equidigital number, since it uses as much as digits as its factorization.
10010110444547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8960, while the sum is 32.
Adding to 10010110444547 its reverse (74544401101001), we get a palindrome (84554511545548).
The spelling of 10010110444547 in words is "ten trillion, ten billion, one hundred ten million, four hundred forty-four thousand, five hundred forty-seven".
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