10010113411 has 4 divisors (see below), whose sum is σ = 10010351800. Its totient is φ = 10009875024.

The previous prime is 10010113397. The next prime is 10010113441. The reversal of 10010113411 is 11431101001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11431101001 = 13259 ⋅862139.

It is a cyclic number.

It is not a de Polignac number, because 10010113411 - 2²⁵ = 9976558979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10010113391 and 10010113400.

It is not an unprimeable number, because it can be changed into a prime (10010113441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37581 + ... + 146398.

It is an arithmetic number, because the mean of its divisors is an integer number (2502587950).

Almost surely, 2^10010113411 is an apocalyptic number.

10010113411 is a deficient number, since it is larger than the sum of its proper divisors (238389).

10010113411 is an equidigital number, since it uses as much as digits as its factorization.

10010113411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 238388.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10010113411 its reverse (11431101001), we get a palindrome (21441214412).

The spelling of 10010113411 in words is "ten billion, ten million, one hundred thirteen thousand, four hundred eleven".