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1001021002013 is a prime number
BaseRepresentation
bin11101001000100011000…
…00000101000100011101
310112200210212121200221102
432210101200011010131
5112400042334031023
62043510202042445
7132215143061204
oct16442140050435
93480725550842
101001021002013
1135659229390a
12142007aa9425
137351b97a246
1436641ca023b
151b08b1e5628
hexe91180511d

1001021002013 has 2 divisors, whose sum is σ = 1001021002014. Its totient is φ = 1001021002012.

The previous prime is 1001021001989. The next prime is 1001021002027. The reversal of 1001021002013 is 3102001201001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 685893706969 + 315127295044 = 828187^2 + 561362^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001021002013 - 216 = 1001020936477 is a prime.

It is a super-2 number, since 2×10010210020132 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001021001985 and 1001021002003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001021002073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500510501006 + 500510501007.

It is an arithmetic number, because the mean of its divisors is an integer number (500510501007).

Almost surely, 21001021002013 is an apocalyptic number.

It is an amenable number.

1001021002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001021002013 is an equidigital number, since it uses as much as digits as its factorization.

1001021002013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 1001021002013 its reverse (3102001201001), we get a palindrome (4103022203014).

The spelling of 1001021002013 in words is "one trillion, one billion, twenty-one million, two thousand, thirteen".