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100102121111011 is a prime number
BaseRepresentation
bin10110110000101011010111…
…010111101011110111100011
3111010102200001221012110211111
4112300223113113223313203
5101110033121001023021
6552522140220324151
730041065610231665
oct2660532727536743
9433380057173744
10100102121111011
112999408678a388
12b2885659a3657
1343b1788225556
141aa0d7b856535
15b88d44d418e1
hex5b0ad75ebde3

100102121111011 has 2 divisors, whose sum is σ = 100102121111012. Its totient is φ = 100102121111010.

The previous prime is 100102121110993. The next prime is 100102121111017. The reversal of 100102121111011 is 110111121201001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100102121111011 - 215 = 100102121078243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100102121110982 and 100102121111000.

It is not a weakly prime, because it can be changed into another prime (100102121111017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50051060555505 + 50051060555506.

It is an arithmetic number, because the mean of its divisors is an integer number (50051060555506).

Almost surely, 2100102121111011 is an apocalyptic number.

100102121111011 is a deficient number, since it is larger than the sum of its proper divisors (1).

100102121111011 is an equidigital number, since it uses as much as digits as its factorization.

100102121111011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 100102121111011 its reverse (110111121201001), we get a palindrome (210213242312012).

The spelling of 100102121111011 in words is "one hundred trillion, one hundred two billion, one hundred twenty-one million, one hundred eleven thousand, eleven".