Base | Representation |
---|---|
bin | 10010101001010100… |
… | …10011110111000011 |
3 | 221211122011112201011 |
4 | 21110222103313003 |
5 | 131000114442011 |
6 | 4333151421351 |
7 | 503031151321 |
oct | 112452236703 |
9 | 27748145634 |
10 | 10010312131 |
11 | 4277618736 |
12 | 1b34524857 |
13 | c36b8b121 |
14 | 6ad688d11 |
15 | 3d8c48621 |
hex | 254a93dc3 |
10010312131 has 2 divisors, whose sum is σ = 10010312132. Its totient is φ = 10010312130.
The previous prime is 10010312119. The next prime is 10010312141. The reversal of 10010312131 is 13121301001.
10010312131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10010312131 - 217 = 10010181059 is a prime.
It is a super-2 number, since 2×100103121312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10010312141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005156065 + 5005156066.
It is an arithmetic number, because the mean of its divisors is an integer number (5005156066).
Almost surely, 210010312131 is an apocalyptic number.
10010312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010312131 is an equidigital number, since it uses as much as digits as its factorization.
10010312131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 10010312131 its reverse (13121301001), we get a palindrome (23131613132).
The spelling of 10010312131 in words is "ten billion, ten million, three hundred twelve thousand, one hundred thirty-one".
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