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10010343323111 = 25913863505721
BaseRepresentation
bin1001000110101011011011…
…1101010011010111100111
31022102222110001000111201112
42101222312331103113213
52303002140342314421
633142404354215235
72052136432214255
oct221526675232747
938388401014645
1010010343323111
11320a3a992283a
1211580a388451b
13577c82001a61
14268708b015d5
151255d301b45b
hex91ab6f535e7

10010343323111 has 4 divisors (see below), whose sum is σ = 10014206831424. Its totient is φ = 10006479814800.

The previous prime is 10010343323093. The next prime is 10010343323117. The reversal of 10010343323111 is 11132334301001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10010343323111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10010343323117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1931750270 + ... + 1931755451.

It is an arithmetic number, because the mean of its divisors is an integer number (2503551707856).

Almost surely, 210010343323111 is an apocalyptic number.

10010343323111 is a deficient number, since it is larger than the sum of its proper divisors (3863508313).

10010343323111 is an equidigital number, since it uses as much as digits as its factorization.

10010343323111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3863508312.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 10010343323111 its reverse (11132334301001), we get a palindrome (21142677624112).

The spelling of 10010343323111 in words is "ten trillion, ten billion, three hundred forty-three million, three hundred twenty-three thousand, one hundred eleven".

Divisors: 1 2591 3863505721 10010343323111