100110021001217 has 2 divisors, whose sum is σ = 100110021001218. Its totient is φ = 100110021001216.

The previous prime is 100110021001153. The next prime is 100110021001219. The reversal of 100110021001217 is 712100120011001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99090696533761 + 1019324467456 = 9954431^2 + 1009616^2 .

It is a cyclic number.

It is not a de Polignac number, because 100110021001217 - 2⁶ = 100110021001153 is a prime.

It is a super-2 number, since 2×100110021001217² (a number of 29 digits) contains 22 as substring.

Together with 100110021001219, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100110021001195 and 100110021001204.

It is not a weakly prime, because it can be changed into another prime (100110021001219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055010500608 + 50055010500609.

It is an arithmetic number, because the mean of its divisors is an integer number (50055010500609).

Almost surely, 2^{100110021001217} is an apocalyptic number.

It is an amenable number.

100110021001217 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110021001217 is an equidigital number, since it uses as much as digits as its factorization.

100110021001217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 100110021001217 its reverse (712100120011001), we get a palindrome (812210141012218).

The spelling of 100110021001217 in words is "one hundred trillion, one hundred ten billion, twenty-one million, one thousand, two hundred seventeen".