Base | Representation |
---|---|
bin | 10010101001011001… |
… | …11110010000000111 |
3 | 221211200111000002012 |
4 | 21110230332100013 |
5 | 131000304310210 |
6 | 4333214404435 |
7 | 503040116144 |
oct | 112454762007 |
9 | 27750430065 |
10 | 10011010055 |
11 | 4277a55032 |
12 | 1b3480071b |
13 | c370739b7 |
14 | 6ad7cb3cb |
15 | 3d8d35305 |
hex | 254b3e407 |
10011010055 has 4 divisors (see below), whose sum is σ = 12013212072. Its totient is φ = 8008808040.
The previous prime is 10011009977. The next prime is 10011010067. The reversal of 10011010055 is 55001011001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55001011001 = 7349 ⋅7484149.
It is not a de Polignac number, because 10011010055 - 222 = 10006815751 is a prime.
It is a super-2 number, since 2×100110100552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001101001 + ... + 1001101010.
It is an arithmetic number, because the mean of its divisors is an integer number (3003303018).
Almost surely, 210011010055 is an apocalyptic number.
10011010055 is a deficient number, since it is larger than the sum of its proper divisors (2002202017).
10011010055 is an equidigital number, since it uses as much as digits as its factorization.
10011010055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2002202016.
The product of its (nonzero) digits is 25, while the sum is 14.
Adding to 10011010055 its reverse (55001011001), we get a palindrome (65012021056).
The spelling of 10011010055 in words is "ten billion, eleven million, ten thousand, fifty-five".
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