Search a number
-
+
10011011000951 is a prime number
BaseRepresentation
bin1001000110101101111011…
…0000010010101001110111
31022110001011120101001112102
42101223132300102221313
52303010022304012301
633142554525012315
72052162120326012
oct221533660225167
938401146331472
1010011011000951
11320a7117a6004
12115824b3b409b
1357805a4351bc
1426876d664379
15125621956b6b
hex91adec12a77

10011011000951 has 2 divisors, whose sum is σ = 10011011000952. Its totient is φ = 10011011000950.

The previous prime is 10011011000923. The next prime is 10011011001001. The reversal of 10011011000951 is 15900011011001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10011011000951 is a prime.

It is a super-2 number, since 2×100110110009512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011011000651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005505500475 + 5005505500476.

It is an arithmetic number, because the mean of its divisors is an integer number (5005505500476).

Almost surely, 210011011000951 is an apocalyptic number.

10011011000951 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011011000951 is an equidigital number, since it uses as much as digits as its factorization.

10011011000951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 20.

Adding to 10011011000951 its reverse (15900011011001), we get a palindrome (25911022011952).

The spelling of 10011011000951 in words is "ten trillion, eleven billion, eleven million, nine hundred fifty-one", and thus it is an aban number.