Base | Representation |
---|---|
bin | 1001000110101101111011… |
… | …0000010010101001110111 |
3 | 1022110001011120101001112102 |
4 | 2101223132300102221313 |
5 | 2303010022304012301 |
6 | 33142554525012315 |
7 | 2052162120326012 |
oct | 221533660225167 |
9 | 38401146331472 |
10 | 10011011000951 |
11 | 320a7117a6004 |
12 | 115824b3b409b |
13 | 57805a4351bc |
14 | 26876d664379 |
15 | 125621956b6b |
hex | 91adec12a77 |
10011011000951 has 2 divisors, whose sum is σ = 10011011000952. Its totient is φ = 10011011000950.
The previous prime is 10011011000923. The next prime is 10011011001001. The reversal of 10011011000951 is 15900011011001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10011011000951 is a prime.
It is a super-2 number, since 2×100110110009512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10011011000651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005505500475 + 5005505500476.
It is an arithmetic number, because the mean of its divisors is an integer number (5005505500476).
Almost surely, 210011011000951 is an apocalyptic number.
10011011000951 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011011000951 is an equidigital number, since it uses as much as digits as its factorization.
10011011000951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45, while the sum is 20.
Adding to 10011011000951 its reverse (15900011011001), we get a palindrome (25911022011952).
The spelling of 10011011000951 in words is "ten trillion, eleven billion, eleven million, nine hundred fifty-one", and thus it is an aban number.
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