Base | Representation |
---|---|
bin | 101110100111100000… |
… | …1110011101011011101 |
3 | 100120101211212002210221 |
4 | 1131033001303223131 |
5 | 3120011142343233 |
6 | 113553455201341 |
7 | 10142551665001 |
oct | 1351701635335 |
9 | 316354762727 |
10 | 100110121693 |
11 | 3950261016a |
12 | 1749a816251 |
13 | 95955882ca |
14 | 4bb9928701 |
15 | 290dc3d42d |
hex | 174f073add |
100110121693 has 2 divisors, whose sum is σ = 100110121694. Its totient is φ = 100110121692.
The previous prime is 100110121681. The next prime is 100110121697. The reversal of 100110121693 is 396121011001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56824070884 + 43286050809 = 238378^2 + 208053^2 .
It is an emirp because it is prime and its reverse (396121011001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100110121693 - 213 = 100110113501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100110121697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055060846 + 50055060847.
It is an arithmetic number, because the mean of its divisors is an integer number (50055060847).
Almost surely, 2100110121693 is an apocalyptic number.
It is an amenable number.
100110121693 is a deficient number, since it is larger than the sum of its proper divisors (1).
100110121693 is an equidigital number, since it uses as much as digits as its factorization.
100110121693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
Adding to 100110121693 its reverse (396121011001), we get a palindrome (496231132694).
The spelling of 100110121693 in words is "one hundred billion, one hundred ten million, one hundred twenty-one thousand, six hundred ninety-three".
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