Base | Representation |
---|---|
bin | 11101001000101101000… |
… | …10010100000110100101 |
3 | 10112201000202120022122221 |
4 | 32210112202110012211 |
5 | 112400231000131312 |
6 | 2043522420352341 |
7 | 132220220061121 |
oct | 16442642240645 |
9 | 3481022508587 |
10 | 1001105473957 |
11 | 356625a39936 |
12 | 1420302456b1 |
13 | 73533314c44 |
14 | 3664d1ac581 |
15 | 1b09382e207 |
hex | e9168941a5 |
1001105473957 has 2 divisors, whose sum is σ = 1001105473958. Its totient is φ = 1001105473956.
The previous prime is 1001105473939. The next prime is 1001105473999. The reversal of 1001105473957 is 7593745011001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 991207412836 + 9898061121 = 995594^2 + 99489^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1001105473957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001105473657) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500552736978 + 500552736979.
It is an arithmetic number, because the mean of its divisors is an integer number (500552736979).
Almost surely, 21001105473957 is an apocalyptic number.
It is an amenable number.
1001105473957 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001105473957 is an equidigital number, since it uses as much as digits as its factorization.
1001105473957 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 132300, while the sum is 43.
The spelling of 1001105473957 in words is "one trillion, one billion, one hundred five million, four hundred seventy-three thousand, nine hundred fifty-seven".
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