1001110101311 has 2 divisors, whose sum is σ = 1001110101312. Its totient is φ = 1001110101310.

The previous prime is 1001110101283. The next prime is 1001110101319. The reversal of 1001110101311 is 1131010111001.

It is a strong prime.

It is an emirp because it is prime and its reverse (1131010111001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001110101311 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001110101292 and 1001110101301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001110101319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500555050655 + 500555050656.

It is an arithmetic number, because the mean of its divisors is an integer number (500555050656).

Almost surely, 2^{1001110101311} is an apocalyptic number.

1001110101311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001110101311 is an equidigital number, since it uses as much as digits as its factorization.

1001110101311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 1001110101311 its reverse (1131010111001), we get a palindrome (2132120212312).

The spelling of 1001110101311 in words is "one trillion, one billion, one hundred ten million, one hundred one thousand, three hundred eleven".