1001112002113 has 2 divisors, whose sum is σ = 1001112002114. Its totient is φ = 1001112002112.

The previous prime is 1001112002071. The next prime is 1001112002131. The reversal of 1001112002113 is 3112002111001.

It is a happy number.

Together with next prime (1001112002131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 993085992369 + 8026009744 = 996537^2 + 89588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001112002113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001112002093 and 1001112002102.

It is not a weakly prime, because it can be changed into another prime (1001112002413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500556001056 + 500556001057.

It is an arithmetic number, because the mean of its divisors is an integer number (500556001057).

Almost surely, 2^{1001112002113} is an apocalyptic number.

It is an amenable number.

1001112002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001112002113 is an equidigital number, since it uses as much as digits as its factorization.

1001112002113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1001112002113 its reverse (3112002111001), we get a palindrome (4113114113114).

The spelling of 1001112002113 in words is "one trillion, one billion, one hundred twelve million, two thousand, one hundred thirteen".