Base | Representation |
---|---|
bin | 10010101001011011… |
… | …10001100000101101 |
3 | 221211200212200002102 |
4 | 21110231301200231 |
5 | 131000333020023 |
6 | 4333223104445 |
7 | 503041652234 |
oct | 112455614055 |
9 | 27750780072 |
10 | 10011220013 |
11 | 4278088853 |
12 | 1b348a2125 |
13 | c37118432 |
14 | 6ad843b1b |
15 | 3d8d77628 |
hex | 254b7182d |
10011220013 has 2 divisors, whose sum is σ = 10011220014. Its totient is φ = 10011220012.
The previous prime is 10011219997. The next prime is 10011220039. The reversal of 10011220013 is 31002211001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9777649924 + 233570089 = 98882^2 + 15283^2 .
It is an emirp because it is prime and its reverse (31002211001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10011220013 - 24 = 10011219997 is a prime.
It is a super-2 number, since 2×100112200132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10011219976 and 10011220003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10031220013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005610006 + 5005610007.
It is an arithmetic number, because the mean of its divisors is an integer number (5005610007).
Almost surely, 210011220013 is an apocalyptic number.
It is an amenable number.
10011220013 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011220013 is an equidigital number, since it uses as much as digits as its factorization.
10011220013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 10011220013 its reverse (31002211001), we get a palindrome (41013431014).
The spelling of 10011220013 in words is "ten billion, eleven million, two hundred twenty thousand, thirteen".
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