Base | Representation |
---|---|
bin | 10110110000110100110000… |
… | …001000011000010000100111 |
3 | 111010110122002100210111222212 |
4 | 112300310300020120100213 |
5 | 101110214241223032401 |
6 | 552530524310314035 |
7 | 30041603435145455 |
oct | 2660646010302047 |
9 | 433418070714885 |
10 | 100112200205351 |
11 | 29998389107114 |
12 | b28a4b935891b |
13 | 43b2703416ab9 |
14 | 1aa16562c79d5 |
15 | b89234b24dbb |
hex | 5b0d30218427 |
100112200205351 has 4 divisors (see below), whose sum is σ = 100112620689312. Its totient is φ = 100111779721392.
The previous prime is 100112200205317. The next prime is 100112200205389. The reversal of 100112200205351 is 153502002211001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100112200205351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100112200208351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209884646 + ... + 210361091.
It is an arithmetic number, because the mean of its divisors is an integer number (25028155172328).
Almost surely, 2100112200205351 is an apocalyptic number.
100112200205351 is a deficient number, since it is larger than the sum of its proper divisors (420483961).
100112200205351 is an equidigital number, since it uses as much as digits as its factorization.
100112200205351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 420483960.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 100112200205351 its reverse (153502002211001), we get a palindrome (253614202416352).
The spelling of 100112200205351 in words is "one hundred trillion, one hundred twelve billion, two hundred million, two hundred five thousand, three hundred fifty-one".
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