Base | Representation |
---|---|
bin | 101110100111100100… |
… | …1101111100101110111 |
3 | 100120101222202210121011 |
4 | 1131033021233211313 |
5 | 3120012210431403 |
6 | 113554011533051 |
7 | 10142605451224 |
oct | 1351711574567 |
9 | 316358683534 |
10 | 100112202103 |
11 | 39503801211 |
12 | 1749b45a187 |
13 | 9595b36214 |
14 | 4bb9d0a94b |
15 | 290deeea6d |
hex | 174f26f977 |
100112202103 has 2 divisors, whose sum is σ = 100112202104. Its totient is φ = 100112202102.
The previous prime is 100112202059. The next prime is 100112202133. The reversal of 100112202103 is 301202211001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100112202103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100112202133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056101051 + 50056101052.
It is an arithmetic number, because the mean of its divisors is an integer number (50056101052).
Almost surely, 2100112202103 is an apocalyptic number.
100112202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112202103 is an equidigital number, since it uses as much as digits as its factorization.
100112202103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 100112202103 its reverse (301202211001), we get a palindrome (401314413104).
The spelling of 100112202103 in words is "one hundred billion, one hundred twelve million, two hundred two thousand, one hundred three".
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