1001123113 has 2 divisors, whose sum is σ = 1001123114. Its totient is φ = 1001123112.

The previous prime is 1001123111. The next prime is 1001123131. The reversal of 1001123113 is 3113211001.

Together with next prime (1001123131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 922215424 + 78907689 = 30368^2 + 8883^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001123113 - 2¹ = 1001123111 is a prime.

Together with 1001123111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1001123093 and 1001123102.

It is not a weakly prime, because it can be changed into another prime (1001123111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500561556 + 500561557.

It is an arithmetic number, because the mean of its divisors is an integer number (500561557).

Almost surely, 2^1001123113 is an apocalyptic number.

It is an amenable number.

1001123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001123113 is an equidigital number, since it uses as much as digits as its factorization.

1001123113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1001123113 is about 31640.5295941771. The cubic root of 1001123113 is about 1000.3742309337.

Adding to 1001123113 its reverse (3113211001), we get a palindrome (4114334114).

It can be divided in two parts, 10011 and 23113, that added together give a square (33124 = 182²).

The spelling of 1001123113 in words is "one billion, one million, one hundred twenty-three thousand, one hundred thirteen".