10011312100313 has 4 divisors (see below), whose sum is σ = 10334257651968. Its totient is φ = 9688366548660.

The previous prime is 10011312100301. The next prime is 10011312100469. The reversal of 10011312100313 is 31300121311001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10011312100313 - 2⁸ = 10011312100057 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10011312100291 and 10011312100300.

It is not an unprimeable number, because it can be changed into a prime (10011312100213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161472775781 + ... + 161472775842.

It is an arithmetic number, because the mean of its divisors is an integer number (2583564412992).

Almost surely, 2^{10011312100313} is an apocalyptic number.

It is an amenable number.

10011312100313 is a deficient number, since it is larger than the sum of its proper divisors (322945551655).

10011312100313 is an equidigital number, since it uses as much as digits as its factorization.

10011312100313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322945551654.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10011312100313 its reverse (31300121311001), we get a palindrome (41311433411314).

The spelling of 10011312100313 in words is "ten trillion, eleven billion, three hundred twelve million, one hundred thousand, three hundred thirteen".