10011320023 has 4 divisors (see below), whose sum is σ = 10224326880. Its totient is φ = 9798313168.

The previous prime is 10011320021. The next prime is 10011320051. The reversal of 10011320023 is 32002311001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10011320023 - 2¹ = 10011320021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10011319985 and 10011320012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011320021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106503358 + ... + 106503451.

It is an arithmetic number, because the mean of its divisors is an integer number (2556081720).

Almost surely, 2^10011320023 is an apocalyptic number.

10011320023 is a deficient number, since it is larger than the sum of its proper divisors (213006857).

10011320023 is an equidigital number, since it uses as much as digits as its factorization.

10011320023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213006856.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 10011320023 its reverse (32002311001), we get a palindrome (42013631024).

The spelling of 10011320023 in words is "ten billion, eleven million, three hundred twenty thousand, twenty-three".