Base | Representation |
---|---|
bin | 101110100111100110… |
… | …1101011100110100111 |
3 | 100120102001201020120021 |
4 | 1131033031223212213 |
5 | 3120012441444333 |
6 | 113554050020011 |
7 | 10142620310533 |
oct | 1351715534647 |
9 | 316361636507 |
10 | 100113234343 |
11 | 39504346801 |
12 | 1749b877607 |
13 | 9596108005 |
14 | 4bba0d8bc3 |
15 | 290e15582d |
hex | 174f36b9a7 |
100113234343 has 8 divisors (see below), whose sum is σ = 107109932720. Its totient is φ = 93289294080.
The previous prime is 100113234329. The next prime is 100113234409. The reversal of 100113234343 is 343432311001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100113234343 - 217 = 100113103271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100113234643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43188330 + ... + 43190647.
It is an arithmetic number, because the mean of its divisors is an integer number (13388741590).
Almost surely, 2100113234343 is an apocalyptic number.
100113234343 is a deficient number, since it is larger than the sum of its proper divisors (6996698377).
100113234343 is an equidigital number, since it uses as much as digits as its factorization.
100113234343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86379057.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 100113234343 its reverse (343432311001), we get a palindrome (443545545344).
The spelling of 100113234343 in words is "one hundred billion, one hundred thirteen million, two hundred thirty-four thousand, three hundred forty-three".
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