10011413011 has 2 divisors, whose sum is σ = 10011413012. Its totient is φ = 10011413010.

The previous prime is 10011412993. The next prime is 10011413051. The reversal of 10011413011 is 11031411001.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10011413011 - 2¹⁵ = 10011380243 is a prime.

It is a super-2 number, since 2×10011413011² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10011412982 and 10011413000.

It is not a weakly prime, because it can be changed into another prime (10011413051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005706505 + 5005706506.

It is an arithmetic number, because the mean of its divisors is an integer number (5005706506).

Almost surely, 2^10011413011 is an apocalyptic number.

10011413011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011413011 is an equidigital number, since it uses as much as digits as its factorization.

10011413011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10011413011 its reverse (11031411001), we get a palindrome (21042824012).

The spelling of 10011413011 in words is "ten billion, eleven million, four hundred thirteen thousand, eleven".