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10011415013 is a prime number
BaseRepresentation
bin10010101001011101…
…00001000111100101
3221211201020120120122
421110232201013211
5131000410240023
64333231211325
7503043423605
oct112456410745
927751216518
1010011415013
114278201306
121b34976b45
13c37186112
146ad894c05
153d8db52c8
hex254ba11e5

10011415013 has 2 divisors, whose sum is σ = 10011415014. Its totient is φ = 10011415012.

The previous prime is 10011414991. The next prime is 10011415027. The reversal of 10011415013 is 31051411001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5044266529 + 4967148484 = 71023^2 + 70478^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011415013 - 26 = 10011414949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011414982 and 10011415000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011415093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005707506 + 5005707507.

It is an arithmetic number, because the mean of its divisors is an integer number (5005707507).

Almost surely, 210011415013 is an apocalyptic number.

It is an amenable number.

10011415013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011415013 is an equidigital number, since it uses as much as digits as its factorization.

10011415013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 10011415013 its reverse (31051411001), we get a palindrome (41062826014).

The spelling of 10011415013 in words is "ten billion, eleven million, four hundred fifteen thousand, thirteen".