Base | Representation |
---|---|
bin | 101110100111101010… |
… | …0011101011111010101 |
3 | 100120102012001112102102 |
4 | 1131033110131133111 |
5 | 3120013420332131 |
6 | 113554152051445 |
7 | 10142641362056 |
oct | 1351724353725 |
9 | 316365045372 |
10 | 100115011541 |
11 | 3950534aa66 |
12 | 174a0393b85 |
13 | 95965aabcc |
14 | 4bba43c72d |
15 | 290e3a71cb |
hex | 174f51d7d5 |
100115011541 has 2 divisors, whose sum is σ = 100115011542. Its totient is φ = 100115011540.
The previous prime is 100115011519. The next prime is 100115011553. The reversal of 100115011541 is 145110511001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78467774641 + 21647236900 = 280121^2 + 147130^2 .
It is a cyclic number.
It is not a de Polignac number, because 100115011541 - 210 = 100115010517 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100115014541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50057505770 + 50057505771.
It is an arithmetic number, because the mean of its divisors is an integer number (50057505771).
Almost surely, 2100115011541 is an apocalyptic number.
It is an amenable number.
100115011541 is a deficient number, since it is larger than the sum of its proper divisors (1).
100115011541 is an equidigital number, since it uses as much as digits as its factorization.
100115011541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100, while the sum is 20.
Adding to 100115011541 its reverse (145110511001), we get a palindrome (245225522542).
The spelling of 100115011541 in words is "one hundred billion, one hundred fifteen million, eleven thousand, five hundred forty-one".
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