Base | Representation |
---|---|
bin | 101110100111110011… |
… | …1011111011001101111 |
3 | 100120102112102222110021 |
4 | 1131033213133121233 |
5 | 3120021210000421 |
6 | 113554451023011 |
7 | 10143031650025 |
oct | 1351747373157 |
9 | 316375388407 |
10 | 100120000111 |
11 | 39508147a4a |
12 | 174a1b9aa67 |
13 | 9597636721 |
14 | 4bbad7a715 |
15 | 290ea40341 |
hex | 174f9df66f |
100120000111 has 2 divisors, whose sum is σ = 100120000112. Its totient is φ = 100120000110.
The previous prime is 100120000087. The next prime is 100120000117. The reversal of 100120000111 is 111000021001.
It is a strong prime.
It is an emirp because it is prime and its reverse (111000021001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100120000111 - 211 = 100119998063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100120000094 and 100120000103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100120000117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060000055 + 50060000056.
It is an arithmetic number, because the mean of its divisors is an integer number (50060000056).
Almost surely, 2100120000111 is an apocalyptic number.
100120000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120000111 is an equidigital number, since it uses as much as digits as its factorization.
100120000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2, while the sum is 7.
Adding to 100120000111 its reverse (111000021001), we get a palindrome (211120021112).
The spelling of 100120000111 in words is "one hundred billion, one hundred twenty million, one hundred eleven", and thus it is an aban number.
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