100120000117 has 2 divisors, whose sum is σ = 100120000118. Its totient is φ = 100120000116.

The previous prime is 100120000111. The next prime is 100120000151. The reversal of 100120000117 is 711000021001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57911941201 + 42208058916 = 240649^2 + 205446^2 .

It is an emirp because it is prime and its reverse (711000021001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100120000117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100120000097 and 100120000106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100120000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060000058 + 50060000059.

It is an arithmetic number, because the mean of its divisors is an integer number (50060000059).

Almost surely, 2^100120000117 is an apocalyptic number.

It is an amenable number.

100120000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120000117 is an equidigital number, since it uses as much as digits as its factorization.

100120000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 13.

Adding to 100120000117 its reverse (711000021001), we get a palindrome (811120021118).

The spelling of 100120000117 in words is "one hundred billion, one hundred twenty million, one hundred seventeen", and thus it is an aban number.