Base | Representation |
---|---|
bin | 10110110000111100000001… |
… | …001010010100110110111011 |
3 | 111010111101020002110220110011 |
4 | 112300330001022110312323 |
5 | 101110331231020334042 |
6 | 552534254412402351 |
7 | 30042300662300611 |
oct | 2660740112246673 |
9 | 433441202426404 |
10 | 100120002121147 |
11 | 299a072208aa08 |
12 | b28bb161763b7 |
13 | 43b33778c3918 |
14 | 1aa1b9654b6b1 |
15 | b8953ea43a17 |
hex | 5b0f01294dbb |
100120002121147 has 2 divisors, whose sum is σ = 100120002121148. Its totient is φ = 100120002121146.
The previous prime is 100120002121049. The next prime is 100120002121193. The reversal of 100120002121147 is 741121200021001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100120002121147 - 211 = 100120002119099 is a prime.
It is not a weakly prime, because it can be changed into another prime (100120002161147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060001060573 + 50060001060574.
It is an arithmetic number, because the mean of its divisors is an integer number (50060001060574).
Almost surely, 2100120002121147 is an apocalyptic number.
100120002121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120002121147 is an equidigital number, since it uses as much as digits as its factorization.
100120002121147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 100120002121147 its reverse (741121200021001), we get a palindrome (841241202142148).
The spelling of 100120002121147 in words is "one hundred trillion, one hundred twenty billion, two million, one hundred twenty-one thousand, one hundred forty-seven".
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