Base | Representation |
---|---|
bin | 10110110000111100000001… |
… | …101001001011101011100111 |
3 | 111010111101020122200212022011 |
4 | 112300330001221023223213 |
5 | 101110331240103210043 |
6 | 552534255302015051 |
7 | 30042301121120416 |
oct | 2660740151135347 |
9 | 433441218625264 |
10 | 100120010210023 |
11 | 299a0726705231 |
12 | b28bb18a17487 |
13 | 43b337949663b |
14 | 1aa1b9765547d |
15 | b895405e059d |
hex | 5b0f01a4bae7 |
100120010210023 has 2 divisors, whose sum is σ = 100120010210024. Its totient is φ = 100120010210022.
The previous prime is 100120010210009. The next prime is 100120010210093. The reversal of 100120010210023 is 320012010021001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100120010210023 - 29 = 100120010209511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100120010209985 and 100120010210012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100120010210093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060005105011 + 50060005105012.
It is an arithmetic number, because the mean of its divisors is an integer number (50060005105012).
Almost surely, 2100120010210023 is an apocalyptic number.
100120010210023 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120010210023 is an equidigital number, since it uses as much as digits as its factorization.
100120010210023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 100120010210023 its reverse (320012010021001), we get a palindrome (420132020231024).
The spelling of 100120010210023 in words is "one hundred trillion, one hundred twenty billion, ten million, two hundred ten thousand, twenty-three".
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