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100120200007 is a prime number
BaseRepresentation
bin101110100111110100…
…0010000001101000111
3100120102112211010122211
41131033220100031013
53120021232400012
6113554455204251
710143033441562
oct1351750201507
9316375733584
10100120200007
1139508274153
12174a2076687
1395976a66c9
144bbadcd4d9
15290ea7e6a7
hex174fa10347

100120200007 has 2 divisors, whose sum is σ = 100120200008. Its totient is φ = 100120200006.

The previous prime is 100120199953. The next prime is 100120200023. The reversal of 100120200007 is 700002021001.

It is a strong prime.

It is an emirp because it is prime and its reverse (700002021001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100120200007 - 223 = 100111811399 is a prime.

It is a super-4 number, since 4×1001202000074 (a number of 45 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100120200007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100120200107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060100003 + 50060100004.

It is an arithmetic number, because the mean of its divisors is an integer number (50060100004).

Almost surely, 2100120200007 is an apocalyptic number.

100120200007 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120200007 is an equidigital number, since it uses as much as digits as its factorization.

100120200007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 13.

Adding to 100120200007 its reverse (700002021001), we get a palindrome (800122221008).

The spelling of 100120200007 in words is "one hundred billion, one hundred twenty million, two hundred thousand, seven".