10012021100113 has 2 divisors, whose sum is σ = 10012021100114. Its totient is φ = 10012021100112.

The previous prime is 10012021100099. The next prime is 10012021100117. The reversal of 10012021100113 is 31100112021001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6044945070609 + 3967076029504 = 2458647^2 + 1991752^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10012021100113 is a prime.

It is a super-2 number, since 2×10012021100113² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10012021100093 and 10012021100102.

It is not a weakly prime, because it can be changed into another prime (10012021100117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006010550056 + 5006010550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5006010550057).

Almost surely, 2^{10012021100113} is an apocalyptic number.

It is an amenable number.

10012021100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012021100113 is an equidigital number, since it uses as much as digits as its factorization.

10012021100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10012021100113 its reverse (31100112021001), we get a palindrome (41112133121114).

The spelling of 10012021100113 in words is "ten trillion, twelve billion, twenty-one million, one hundred thousand, one hundred thirteen".