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100120433 = 735939841
BaseRepresentation
bin1011111011110…
…11011101110001
320222101122102012
411331323131301
5201112323213
613533532305
72324003210
oct575733561
9228348365
10100120433
1151573a66
1229644095
131798657a
14d423077
158bca4a8
hex5f7b771

100120433 has 8 divisors (see below), whose sum is σ = 114744960. Its totient is φ = 85576320.

The previous prime is 100120417. The next prime is 100120457. The reversal of 100120433 is 334021001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100120433 - 24 = 100120417 is a prime.

It is a super-2 number, since 2×1001204332 = 20048202208214978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100120733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17408 + ... + 22433.

It is an arithmetic number, because the mean of its divisors is an integer number (14343120).

Almost surely, 2100120433 is an apocalyptic number.

It is an amenable number.

100120433 is a deficient number, since it is larger than the sum of its proper divisors (14624527).

100120433 is an equidigital number, since it uses as much as digits as its factorization.

100120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40207.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 100120433 is about 10006.0198380775. The cubic root of 100120433 is about 464.3451420983.

Adding to 100120433 its reverse (334021001), we get a palindrome (434141434).

The spelling of 100120433 in words is "one hundred million, one hundred twenty thousand, four hundred thirty-three".

Divisors: 1 7 359 2513 39841 278887 14302919 100120433