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100121104313 = 102679751739
BaseRepresentation
bin101110100111110101…
…1101100111110111001
3100120102121112002010122
41131033223230332321
53120022000314223
6113554530423025
710143044226206
oct1351753547671
9316377462118
10100121104313
113950883160a
12174a2431a75
1395979321b9
144bbb186cad
15290ebac5c8
hex174faecfb9

100121104313 has 4 divisors (see below), whose sum is σ = 100130866320. Its totient is φ = 100111342308.

The previous prime is 100121104289. The next prime is 100121104331. The reversal of 100121104313 is 313401121001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100121104313 - 212 = 100121100217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100121104291 and 100121104300.

It is not an unprimeable number, because it can be changed into a prime (100121104913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4865603 + ... + 4886136.

It is an arithmetic number, because the mean of its divisors is an integer number (25032716580).

Almost surely, 2100121104313 is an apocalyptic number.

It is an amenable number.

100121104313 is a deficient number, since it is larger than the sum of its proper divisors (9762007).

100121104313 is an equidigital number, since it uses as much as digits as its factorization.

100121104313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9762006.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 100121104313 its reverse (313401121001), we get a palindrome (413522225314).

The spelling of 100121104313 in words is "one hundred billion, one hundred twenty-one million, one hundred four thousand, three hundred thirteen".

Divisors: 1 10267 9751739 100121104313