Search a number
-
+
10012111110013 is a prime number
BaseRepresentation
bin1001000110110010000001…
…0100110111111101111101
31022110011000020102101110111
42101230200110313331331
52303014300421010023
633143300024110021
72052231306155035
oct221544024677575
938404006371414
1010012111110013
113210126785251
1211584b7905311
135781a43236cc
142688357d08c5
1512568831000d
hex91b20537f7d

10012111110013 has 2 divisors, whose sum is σ = 10012111110014. Its totient is φ = 10012111110012.

The previous prime is 10012111109951. The next prime is 10012111110049. The reversal of 10012111110013 is 31001111121001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5025295108089 + 4986816001924 = 2241717^2 + 2233118^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012111110013 - 225 = 10012077555581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10012111109975 and 10012111110002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012111110413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006055555006 + 5006055555007.

It is an arithmetic number, because the mean of its divisors is an integer number (5006055555007).

Almost surely, 210012111110013 is an apocalyptic number.

It is an amenable number.

10012111110013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012111110013 is an equidigital number, since it uses as much as digits as its factorization.

10012111110013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 10012111110013 its reverse (31001111121001), we get a palindrome (41013222231014).

The spelling of 10012111110013 in words is "ten trillion, twelve billion, one hundred eleven million, one hundred ten thousand, thirteen".