Base | Representation |
---|---|
bin | 1001000110110010000011… |
… | …1011011001110010011101 |
3 | 1022110011000221102112001120 |
4 | 2101230200323121302131 |
5 | 2303014311012210023 |
6 | 33143301024401153 |
7 | 2052231461052066 |
oct | 221544073316235 |
9 | 38404027375046 |
10 | 10012121210013 |
11 | 321013145355a |
12 | 11584bb1761b9 |
13 | 5781a644b940 |
14 | 268836c9d56d |
15 | 1256891578e3 |
hex | 91b20ed9c9d |
10012121210013 has 32 divisors (see below), whose sum is σ = 14742576035712. Its totient is φ = 6004681267200.
The previous prime is 10012121209933. The next prime is 10012121210023. The reversal of 10012121210013 is 31001212121001.
10012121210013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10012121210013 - 29 = 10012121209501 is a prime.
It is a super-2 number, since 2×100121212100132 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10012121209974 and 10012121210001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10012121210023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1791708 + ... + 4820213.
It is an arithmetic number, because the mean of its divisors is an integer number (460705501116).
Almost surely, 210012121210013 is an apocalyptic number.
10012121210013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10012121210013 is a deficient number, since it is larger than the sum of its proper divisors (4730454825699).
10012121210013 is a wasteful number, since it uses less digits than its factorization.
10012121210013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6612925.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 10012121210013 its reverse (31001212121001), we get a palindrome (41013333331014).
It can be divided in two parts, 1001212121001 and 3, that multiplied together give a palindrome (3003636363003).
The spelling of 10012121210013 in words is "ten trillion, twelve billion, one hundred twenty-one million, two hundred ten thousand, thirteen".
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