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100121221147 is a prime number
BaseRepresentation
bin101110100111110110…
…0001001100000011011
3100120102121202000101211
41131033230021200123
53120022013034042
6113554533123551
710143045223633
oct1351754114033
9316377660354
10100121221147
1139508901372
12174a24895b7
13959797342c
144bbb1b76c3
15290ebd2017
hex174fb0981b

100121221147 has 2 divisors, whose sum is σ = 100121221148. Its totient is φ = 100121221146.

The previous prime is 100121221099. The next prime is 100121221169. The reversal of 100121221147 is 741122121001.

It is a happy number.

It is an a-pointer prime, because the next prime (100121221169) can be obtained adding 100121221147 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100121221147 - 27 = 100121221019 is a prime.

It is not a weakly prime, because it can be changed into another prime (100121221177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060610573 + 50060610574.

It is an arithmetic number, because the mean of its divisors is an integer number (50060610574).

Almost surely, 2100121221147 is an apocalyptic number.

100121221147 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121221147 is an equidigital number, since it uses as much as digits as its factorization.

100121221147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 22.

Adding to 100121221147 its reverse (741122121001), we get a palindrome (841243342148).

The spelling of 100121221147 in words is "one hundred billion, one hundred twenty-one million, two hundred twenty-one thousand, one hundred forty-seven".