100121340104433 has 12 divisors (see below), whose sum is σ = 150907527114240. Its totient is φ = 63845492240376.

The previous prime is 100121340104413. The next prime is 100121340104453. The reversal of 100121340104433 is 334401043121001.

100121340104433 is a `hidden beast` number, since 1 + 0 + 0 + 1 + 213 + 4 + 0 + 1 + 0 + 443 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (100121340104413) and next prime (100121340104453).

It is not a de Polignac number, because 100121340104433 - 2²⁸ = 100121071668977 is a prime.

It is a super-2 number, since 2×100121340104433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100121340104397 and 100121340104406.

It is not an unprimeable number, because it can be changed into a prime (100121340104413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 241838985553 + ... + 241838985966.

It is an arithmetic number, because the mean of its divisors is an integer number (12575627259520).

Almost surely, 2^{100121340104433} is an apocalyptic number.

It is an amenable number.

100121340104433 is a deficient number, since it is larger than the sum of its proper divisors (50786187009807).

100121340104433 is a wasteful number, since it uses less digits than its factorization.

100121340104433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 483677971548 (or 483677971545 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 100121340104433 its reverse (334401043121001), we get a palindrome (434522383225434).

The spelling of 100121340104433 in words is "one hundred trillion, one hundred twenty-one billion, three hundred forty million, one hundred four thousand, four hundred thirty-three".