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1001220131 is a prime number
BaseRepresentation
bin111011101011010…
…110100000100011
32120202222020211002
4323223112200203
54022303021011
6243203342215
733545142062
oct7353264043
92522866732
101001220131
1147418755a
1223b38196b
1312c576662
1496d881d9
155cd72c3b
hex3bad6823

1001220131 has 2 divisors, whose sum is σ = 1001220132. Its totient is φ = 1001220130.

The previous prime is 1001220097. The next prime is 1001220133. The reversal of 1001220131 is 1310221001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1001220131 - 226 = 934111267 is a prime.

It is a super-2 number, since 2×10012201312 = 2004883501439314322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 1001220133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1001220133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500610065 + 500610066.

It is an arithmetic number, because the mean of its divisors is an integer number (500610066).

Almost surely, 21001220131 is an apocalyptic number.

1001220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001220131 is an equidigital number, since it uses as much as digits as its factorization.

1001220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1001220131 is about 31642.0626856089. The cubic root of 1001220131 is about 1000.4065450321.

Adding to 1001220131 its reverse (1310221001), we get a palindrome (2311441132).

The spelling of 1001220131 in words is "one billion, one million, two hundred twenty thousand, one hundred thirty-one".