Base | Representation |
---|---|
bin | 11101001000111010110… |
… | …11000000101111001101 |
3 | 10112201022210221122210111 |
4 | 32210131123000233031 |
5 | 112401000034001031 |
6 | 2043542104440021 |
7 | 132223122040135 |
oct | 16443533005715 |
9 | 3481283848714 |
10 | 1001221000141 |
11 | 35668517541a |
12 | 142062a79011 |
13 | 7355123372b |
14 | 36660681ac5 |
15 | 1b09da4e1b1 |
hex | e91d6c0bcd |
1001221000141 has 2 divisors, whose sum is σ = 1001221000142. Its totient is φ = 1001221000140.
The previous prime is 1001221000121. The next prime is 1001221000183. The reversal of 1001221000141 is 1410001221001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 527940294025 + 473280706116 = 726595^2 + 687954^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001221000141 - 237 = 863782046669 is a prime.
It is a super-2 number, since 2×10012210001412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001221000121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500610500070 + 500610500071.
It is an arithmetic number, because the mean of its divisors is an integer number (500610500071).
Almost surely, 21001221000141 is an apocalyptic number.
It is an amenable number.
1001221000141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001221000141 is an equidigital number, since it uses as much as digits as its factorization.
1001221000141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1001221000141 its reverse (1410001221001), we get a palindrome (2411222221142).
The spelling of 1001221000141 in words is "one trillion, one billion, two hundred twenty-one million, one hundred forty-one", and thus it is an aban number.
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