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1001221000141 is a prime number
BaseRepresentation
bin11101001000111010110…
…11000000101111001101
310112201022210221122210111
432210131123000233031
5112401000034001031
62043542104440021
7132223122040135
oct16443533005715
93481283848714
101001221000141
1135668517541a
12142062a79011
137355123372b
1436660681ac5
151b09da4e1b1
hexe91d6c0bcd

1001221000141 has 2 divisors, whose sum is σ = 1001221000142. Its totient is φ = 1001221000140.

The previous prime is 1001221000121. The next prime is 1001221000183. The reversal of 1001221000141 is 1410001221001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 527940294025 + 473280706116 = 726595^2 + 687954^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001221000141 - 237 = 863782046669 is a prime.

It is a super-2 number, since 2×10012210001412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001221000121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500610500070 + 500610500071.

It is an arithmetic number, because the mean of its divisors is an integer number (500610500071).

Almost surely, 21001221000141 is an apocalyptic number.

It is an amenable number.

1001221000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001221000141 is an equidigital number, since it uses as much as digits as its factorization.

1001221000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1001221000141 its reverse (1410001221001), we get a palindrome (2411222221142).

The spelling of 1001221000141 in words is "one trillion, one billion, two hundred twenty-one million, one hundred forty-one", and thus it is an aban number.