100122321113 has 2 divisors, whose sum is σ = 100122321114. Its totient is φ = 100122321112.

The previous prime is 100122321031. The next prime is 100122321149. The reversal of 100122321113 is 311123221001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58521415744 + 41600905369 = 241912^2 + 203963^2 .

It is a cyclic number.

It is not a de Polignac number, because 100122321113 - 2²⁸ = 99853885657 is a prime.

It is a super-3 number, since 3×100122321113³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100122321091 and 100122321100.

It is not a weakly prime, because it can be changed into another prime (100122321613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061160556 + 50061160557.

It is an arithmetic number, because the mean of its divisors is an integer number (50061160557).

Almost surely, 2^100122321113 is an apocalyptic number.

It is an amenable number.

100122321113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122321113 is an equidigital number, since it uses as much as digits as its factorization.

100122321113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 100122321113 its reverse (311123221001), we get a palindrome (411245542114).

The spelling of 100122321113 in words is "one hundred billion, one hundred twenty-two million, three hundred twenty-one thousand, one hundred thirteen".