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10012433441 = 17588966673
BaseRepresentation
bin10010101001100100…
…11001110000100001
3221211210011022121012
421110302121300201
5131001140332231
64333305110305
7503055165023
oct112462316041
927753138535
1010012433441
11427883748a
121b35188395
13c3745183a
146ada7c013
153d9016e2b
hex254c99c21

10012433441 has 4 divisors (see below), whose sum is σ = 10601400132. Its totient is φ = 9423466752.

The previous prime is 10012433381. The next prime is 10012433443. The reversal of 10012433441 is 14433421001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7694973841 + 2317459600 = 87721^2 + 48140^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012433441 - 214 = 10012417057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10012433443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294483320 + ... + 294483353.

It is an arithmetic number, because the mean of its divisors is an integer number (2650350033).

Almost surely, 210012433441 is an apocalyptic number.

It is an amenable number.

10012433441 is a deficient number, since it is larger than the sum of its proper divisors (588966691).

10012433441 is an equidigital number, since it uses as much as digits as its factorization.

10012433441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 588966690.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10012433441 its reverse (14433421001), we get a palindrome (24445854442).

The spelling of 10012433441 in words is "ten billion, twelve million, four hundred thirty-three thousand, four hundred forty-one".

Divisors: 1 17 588966673 10012433441