| Base | Representation |
|---|---|
| bin | 11101001001000100010… |
| … | …00011111011000011000 |
| 3 | 10112201112022122211202100 |
| 4 | 32210202020133120120 |
| 5 | 112401130301443000 |
| 6 | 2043554010403400 |
| 7 | 132225101555613 |
| oct | 16444210373030 |
| 9 | 3481468584670 |
| 10 | 1001300031000 |
| 11 | 356715844485 |
| 12 | 142085430560 |
| 13 | 73564714959 |
| 14 | 3666ad7517a |
| 15 | 1b0a5960a00 |
| hex | e92221f618 |
1001300031000 has 384 divisors, whose sum is σ = 3588025858560. Its totient is φ = 251413632000.
The previous prime is 1001300030981. The next prime is 1001300031001. The reversal of 1001300031000 is 1300031001.
It is a super-2 number, since 2×10013000310002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1001300031001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 10274502 + ... + 10371498.
It is an arithmetic number, because the mean of its divisors is an integer number (9343817340).
Almost surely, 21001300031000 is an apocalyptic number.
1001300031000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1001300031000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1794012929280).
1001300031000 is an abundant number, since it is smaller than the sum of its proper divisors (2586725827560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1001300031000 is a wasteful number, since it uses less digits than its factorization.
1001300031000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97092 (or 97075 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 9.
Adding to 1001300031000 its reverse (1300031001), we get a palindrome (1002600062001).
Subtracting from 1001300031000 its reverse (1300031001), we obtain a palindrome (999999999999).
The spelling of 1001300031000 in words is "one trillion, one billion, three hundred million, thirty-one thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •