Base | Representation |
---|---|
bin | 11101001001000100010… |
… | …01100001000101010001 |
3 | 10112201112100011111220111 |
4 | 32210202021201011101 |
5 | 112401130334100423 |
6 | 2043554020241321 |
7 | 132225104056321 |
oct | 16444211410521 |
9 | 3481470144814 |
10 | 1001300300113 |
11 | 356715a08693 |
12 | 142085540241 |
13 | 735647aa2a9 |
14 | 3666b005281 |
15 | 1b0a59b560d |
hex | e922261151 |
1001300300113 has 8 divisors (see below), whose sum is σ = 1025247872000. Its totient is φ = 977382797328.
The previous prime is 1001300300087. The next prime is 1001300300123. The reversal of 1001300300113 is 3110030031001.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1001300300113 - 217 = 1001300169041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1001300300093 and 1001300300102.
It is not an unprimeable number, because it can be changed into a prime (1001300300123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7449873 + ... + 7583086.
It is an arithmetic number, because the mean of its divisors is an integer number (128155984000).
Almost surely, 21001300300113 is an apocalyptic number.
It is an amenable number.
1001300300113 is a deficient number, since it is larger than the sum of its proper divisors (23947571887).
1001300300113 is a wasteful number, since it uses less digits than its factorization.
1001300300113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15034551.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 1001300300113 its reverse (3110030031001), we get a palindrome (4111330331114).
The spelling of 1001300300113 in words is "one trillion, one billion, three hundred million, three hundred thousand, one hundred thirteen".
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