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10013042003 is a prime number
BaseRepresentation
bin10010101001101001…
…01110010101010011
3221211211022020101112
421110310232111103
5131001314321003
64333330123535
7503063311166
oct112464562523
927754266345
1010013042003
114279112728
121b354205ab
13c37605833
146adb99add
153d90d73d8
hex254d2e553

10013042003 has 2 divisors, whose sum is σ = 10013042004. Its totient is φ = 10013042002.

The previous prime is 10013041999. The next prime is 10013042027. The reversal of 10013042003 is 30024031001.

10013042003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30024031001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10013042003 - 22 = 10013041999 is a prime.

It is a super-2 number, since 2×100130420032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10013044003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006521001 + 5006521002.

It is an arithmetic number, because the mean of its divisors is an integer number (5006521002).

Almost surely, 210013042003 is an apocalyptic number.

10013042003 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013042003 is an equidigital number, since it uses as much as digits as its factorization.

10013042003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 10013042003 its reverse (30024031001), we get a palindrome (40037073004).

The spelling of 10013042003 in words is "ten billion, thirteen million, forty-two thousand, three".