Base | Representation |
---|---|
bin | 101110101000001001… |
… | …0010000001111100011 |
3 | 100120110022112111211011 |
4 | 1131100102100033203 |
5 | 3120032042211321 |
6 | 113555531201351 |
7 | 10143226146364 |
oct | 1352022201743 |
9 | 316408474734 |
10 | 100131210211 |
11 | 3951350429a |
12 | 174a58a6257 |
13 | 9599a60016 |
14 | 4bbc657b6b |
15 | 2910a06ae1 |
hex | 17504903e3 |
100131210211 has 2 divisors, whose sum is σ = 100131210212. Its totient is φ = 100131210210.
The previous prime is 100131210191. The next prime is 100131210229. The reversal of 100131210211 is 112012131001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100131210211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100131210191 and 100131210200.
It is not a weakly prime, because it can be changed into another prime (100131210811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065605105 + 50065605106.
It is an arithmetic number, because the mean of its divisors is an integer number (50065605106).
Almost surely, 2100131210211 is an apocalyptic number.
100131210211 is a deficient number, since it is larger than the sum of its proper divisors (1).
100131210211 is an equidigital number, since it uses as much as digits as its factorization.
100131210211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 100131210211 its reverse (112012131001), we get a palindrome (212143341212).
The spelling of 100131210211 in words is "one hundred billion, one hundred thirty-one million, two hundred ten thousand, two hundred eleven".
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