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10013228026181 is a prime number
BaseRepresentation
bin1001000110110110001011…
…1001100100100101000101
31022110020220002002121101222
42101231202321210211011
52303024042333314211
633144002523330125
72052301060614302
oct221554271444505
938406802077358
1010013228026181
11321064a1a3966
121158769980945
13578321847c53
142688ddc940a9
151257013d81db
hex91b62e64945

10013228026181 has 2 divisors, whose sum is σ = 10013228026182. Its totient is φ = 10013228026180.

The previous prime is 10013228026177. The next prime is 10013228026183. The reversal of 10013228026181 is 18162082231001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5543830357156 + 4469397669025 = 2354534^2 + 2114095^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013228026181 - 22 = 10013228026177 is a prime.

It is a super-2 number, since 2×100132280261812 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10013228026183, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10013228026183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006614013090 + 5006614013091.

It is an arithmetic number, because the mean of its divisors is an integer number (5006614013091).

Almost surely, 210013228026181 is an apocalyptic number.

It is an amenable number.

10013228026181 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013228026181 is an equidigital number, since it uses as much as digits as its factorization.

10013228026181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 35.

The spelling of 10013228026181 in words is "ten trillion, thirteen billion, two hundred twenty-eight million, twenty-six thousand, one hundred eighty-one".