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100133002000999 = 119103000181909
BaseRepresentation
bin10110110001001000001000…
…000000111011101001100111
3111010112121210002001020002201
4112301020020000323221213
5101111034342003012444
6552544244401115331
730043241064405142
oct2661101000735147
9433477702036081
10100133002000999
11299a6193193070
12b292543928b47
1343b4669c52a16
141aa266ac85059
15b89a50e6edd4
hex5b120803ba67

100133002000999 has 4 divisors (see below), whose sum is σ = 109236002182920. Its totient is φ = 91030001819080.

The previous prime is 100133002000979. The next prime is 100133002001009. The reversal of 100133002000999 is 999000200331001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100133002000999 - 223 = 100132993612391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100133002000939) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4551500090944 + ... + 4551500090965.

It is an arithmetic number, because the mean of its divisors is an integer number (27309000545730).

Almost surely, 2100133002000999 is an apocalyptic number.

100133002000999 is a deficient number, since it is larger than the sum of its proper divisors (9103000181921).

100133002000999 is an equidigital number, since it uses as much as digits as its factorization.

100133002000999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9103000181920.

The product of its (nonzero) digits is 13122, while the sum is 37.

The spelling of 100133002000999 in words is "one hundred trillion, one hundred thirty-three billion, two million, nine hundred ninety-nine", and thus it is an aban number.

Divisors: 1 11 9103000181909 100133002000999